3x^2+(x^2-20)=16-2x^2

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Solution for 3x^2+(x^2-20)=16-2x^2 equation: 


Simplifying
3x2 + (x2 + -20) = 16 + -2x2

Reorder the terms:
3x2 + (-20 + x2) = 16 + -2x2

Remove parenthesis around (-20 + x2)
3x2 + -20 + x2 = 16 + -2x2

Reorder the terms:
-20 + 3x2 + x2 = 16 + -2x2

Combine like terms: 3x2 + x2 = 4x2
-20 + 4x2 = 16 + -2x2

Solving
-20 + 4x2 = 16 + -2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2x2' to each side of the equation.
-20 + 4x2 + 2x2 = 16 + -2x2 + 2x2

Combine like terms: 4x2 + 2x2 = 6x2
-20 + 6x2 = 16 + -2x2 + 2x2

Combine like terms: -2x2 + 2x2 = 0
-20 + 6x2 = 16 + 0
-20 + 6x2 = 16

Add '20' to each side of the equation.
-20 + 20 + 6x2 = 16 + 20

Combine like terms: -20 + 20 = 0
0 + 6x2 = 16 + 20
6x2 = 16 + 20

Combine like terms: 16 + 20 = 36
6x2 = 36

Divide each side by '6'.
x2 = 6

Simplifying
x2 = 6

Take the square root of each side:
x = {-2.449489743, 2.449489743}

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